Question

Ina sequence If an= 3n2 +2n then find common difference

Answer 1

Step-by-step explanation:

given

nth term of sequence

$a_{n} = 3 {n}^{2} + 2n \\ \\ a_{n - 1} = 3( {n - 1)}^{2} + 2(n - 1) \\ = 3( {n}^{2} - 2n + 1) + 2n - 2 \\ = 3 {n}^{2} - 6n + 2n + 1 - 2 \\ = 3 {n}^{2} - 4 {n}- 1 \\ \\ common \: \: difference \\ \\ a_{n} - a_{n - 1} = 3 {n}^{2} + 2n - (3 {n}^{2} - 4 {n} - 1) \\ = 6n + 1$