Question

ina temple , there are 50 cylinder pillars . The radius of each pillar is 12 cm and height is 4 cm . Find the cost of painting the curved surface area of pillars at the rate of rupees 6 per m2
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Answer 1

Question :-

• In a temple, there are 50 cylinder pillars. The radius of each pillar is 12 cm and height is 4 cm. Find the cost of painting the curved surface area of pillars at the rate of rupees 6 per m².

Answer :-

Given :-

• Number of cylinderical pillars = 50
• Radius of pillar (r) = 12 cm
• Height of pillar (h) = 4 cm

To Find :-

• The cost of painting the curved surface area of pillars at the rate of rupees 6 per m².

Formula used :-

${\red{ \boxed{\small{\bold\green{Curved \: Surface \: Area _{(Cylinder)}\: = 2 \pi r h }}}}} \:$

where,

• r = radius of cylinder
• h = height of cylinder

Solution :-

Radius of pillar, r = 12 cm

Height of pillar, h = 4 cm

Curved Surface Area of 1 pillar = 2  π r h

${\red{ \boxed{\small{\bold\green{Curved \: Surface \: Area _{(Cylinder)}\: = 2 \pi r h }}}}} \:$

On substituting the values of r and h, we get

$\bf\:Curved \: Surface \: Area = 2 \times \dfrac{22}{7} \times 12 \times 4$

$\bf\implies \:Curved \: Surface \: Area = \dfrac{2112}{7} \: {cm}^{2}$

So, Curved Surface Area of 50 cylinderical pillars

$\bf\implies \:\dfrac{2112}{7} \times 50$

$\bf\implies \:\dfrac{105600}{7} \: {cm}^{2}$

$\bf\implies \:\dfrac{105600}{7} \times \dfrac{1}{10000} {m}^{2}$

$\bf\implies \:\dfrac{10.56}{7} {m}^{2}$

Now, The cost of painting the curved surface area of pillars at the rate of rupees 6 per m²

$\bf\implies \:\dfrac{10.56}{7} \times 6$

$\bf\implies \:₹ \: 9.05$

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Other important Formula's :-

${\red\bigstar\: { \boxed{\large{\bold\green{Volume_{(Cylinder\:block)}\:\leadsto\:\pi r^2 h }}}}} \:★$

${\red\bigstar\: { \boxed{\large{\bold\green{CSA_{(Cylinder\:block)}\:\leadsto\:2\pi r h }}}}} \:★$

${\red\bigstar\: { \boxed{\large{\bold\green{TSA_{(Cylinder\:block)}\:\leadsto\:2\pi r (h + r) }}}}} \:★$

where,

• r = radius of cylinder
• h = height of cylinder
• CSA = Curved Surface Area
• TSA = Total Surface Area

Answer 2

Answer:

this is correct..........................