Ina tennis match a player wins a point by hitting the 0.059-kg ball sharply to the ground on the opponent's side of the net. If the ball bounces upward from the ground with a speed of 16 m/s and is caught by a fan in the stands when it has a speed of 12 m/s, how high above the court is the fan? Ignore air resistance.
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Ina tennis match a player wins a point by hitting the 9.059_kg sharply to the ground on the opponent side of the net. if the ball bounces upward from the ground with a speed
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Given Ina tennis match a player wins a point by hitting the 0.059-kg ball sharply to the ground on the opponent's side of the net. If the ball bounces upward from the ground with a speed of 16 m/s and is caught by a fan in the stands when it has a speed of 12 m/s, how high above the court is the fan? Ignore air resistance.
- Ball bounces upward and gets caught in the stand. So we have
- Kinetic energy at the bottom + potential energy at bottom = kinetic energy at the stands + potential energy at stands.
- So ½ mv^2 + 0 = ½ mv^2 + mgh
- So ½ m x 16^2 + 0 = ½ m x 12^2 + mgh
- So 128 m = ½ m (144 + gh)
- 128 = 72 + gh
- gh = 128 – 72
- h = 56 / g
- Or h = 56 / 10
- Or h = 5.6 mtrs
Reference link will be
https://brainly.in/question/21400878
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