Question

ina triangle ABC, O is a point in its interior. OA, OB and OC are joined. AO is produced, which meets BC at D; similarly, BO and CO meet AC at E and

AB at F, respectively. Prove that

(i) AD < (AB + BC + AC)

(ii) OA + 20F + OB > AB

(iii) 20E < OA + OC + AC​

Answer 1

Answer:

in an side AC come in as side AC