Question

इनर सर्किल टू रेजिस्टर्स ऑफ 4 एंड आर कनेक्टेड इन पैरेलल फाइंड द रेश्यो ऑफ करंट पासिंग थ्रू टू रजिस्टर ​

Answer 1

see the attachment hope it helps

Answer 2

Explanation:

Here, R

1

=4∣∣4=4/2=2Ω and R

2

=6∣∣6=6/2=3Ω

Current in the circuit is I=

R

1

+R

2

V

=

2+3

20

=4A

As (4∣∣4) and (6∣∣6) are in series so same current I will flow through these branches.

In parallel branches two resistances are same so current through each resistance will be I/2=2A