Math, asked by PRINCEEMEHTA, 10 days ago

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Q1. point charges 4Q, Q are separated by lm in air. At what point on the line joining the charges is the electric field intensity zero?Also calculate the electrostatic potential energy of the system of charges, taking the value of charge, Q = 2 ×10^-7C.​

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Answered by sanvi01vyas
5

-The shape of a molecule depends upon the number of electron pairs in the valence shell of the central atom.

-Electron pair in the valence shell repel one another since their electron clouds are negatively charged.

-The electron pairs in the valence shell occupy their position in space around the central atom in a such a way that the distance between them is maximum and the molecule acquires a state of minimum energy and maximum stability.

-The repulsive interactions, of electron pairs decrease in the order

lone pair-lone pair > lone pair-bond pair > bond pair-bond pair

- The repulsion is maximum in the body when the angle is 90⁰ and minimum at 180⁰.

Desperate Banda xD (≧▽≦)

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