INCERT
2. A park in the shape of a quadrilateral ABCD has ZB = 90°, AB = 10 m, BC = 24 m
CD = 18 m and AD = 16m. Find the area of the park.
3
indthefaudrilateral PORS in which PO -9 cm OR - 15 cm RS - 12 cm
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Step-by-step explanation:
ANS :- 2.
In triangle ABC, by Pythagoras theorem
AB² + BC² = AC²
10² + 24²= AC²
100+576=AC²
√676=AC
AC= 26m
Now,
In Tri. ABC
Ar. of Tri. ABC = 1/2 ×10× 24
=120m²
In Tri. ADC
by heron's formula,
s=26+18+16/2
s=30m
Ar.= √30(30-26) (30-18) (30-16)
= 141.98m²
=142m²
So, the total area of quadrilateral ABCD = (142+120)m²
=262m²
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