Question

#include<stdio.h>

/*Function diclaration for calculator*/

float add(float num1,float num2);

float sub(float num1,float num2);

float mult(float num1,float num2);

float div(float num1,float num2);

int main()

{

char operator;

float num1,num2,result=0;



/*print welcome message */

printf("WELCOME TO SIMPLE CALCULATOR\n");

printf("----------------------------\n");

printf("Enter the [number 1] [+,-,*,/] [number 2]\n");

/*Input two number and operactor from user */

scanf("%f %c %f" ,&num1 ,&operator ,&num2);



switch(operator)

{

case '+':

result =add(num1,num2);

break;

case '-':

result =sub(num1 ,num2);

break;

case '*':

result =mult(num1,num2);

break;

case '/':

result =div(num1,num2);

break;

{

if(num2==0)

{

printf("oops divide by zero");

}

else

{

printf("div %f" ,result);

}

}

default:

printf("Invalid operactor");

}

/*print the result*/

printf("%f %c %f = %f" ,num1 ,operator ,num2 , result);

return 0;

}

/*Function to Add two number*/

float add(float num1, float num2)

{

return num1+num2;

}

/*Function to Subtract two number*/

float sub(float num1, float num2)

{

return num1-num2;

}

/*Function to multiply two number*/

float mult(float num1, float num2)

{

return num1*num2;

}

/*Function to divide two number*/

float div(float num1, float num2)

{

return num1/num2;

}

Can anyone understand why if conditions is not execute ​

Answer 1

Answer:

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