Question

#include<stdio.h>
#include<stdlib.h>
#define MAX 20
void printsparse(int b[MAX][3]);
void readsparse(int b[MAX][3]);
void addsparse(int b1[MAX][3],int
b2[MAX][3],int b3[MAX][3]);
void main()
{
int b1[MAX][3],b2[MAX][3],b3[MAX][3];
readsparse(b1);
readsparse(b2);
addsparse(b1,b2,b3);
printsparse(b3);
}
void readsparse(int b[MAX][3])
{
int i,t,m,n;
printf("\nEnter no. of rows and columns: ");
scanf("%d%d",&m,&n);
printf("\n No. of non-zero triples:");
scanf("%d",&t);
b[0][0]=m;
b[0][1]=n;
b[0][2]=t;
for(i=1;i<=t;i++)
{
printf("\n Enter the triples(row,column,value):");
scanf("%d%d%d",&b[i][0],&b[i][1],&b[i][2]);
}
}
void addsparse(int b1[MAX][3],int b2[MAX][3],int b3[MAX][3])
{
int t1,t2,i,j,k;
if(b1[0][0]!=b2[0][0]||b1[0][1]!=b2[0][1])
{
printf("\n You have entered invalid matrix!!Size must be equal");
exit(0);
}
t1=b1[0][2];
t2=b2[0][2];
i=j=k=0;
b3[0][0]=b1[0][0];
b3[0][1]=b1[0][1];
while(i<=t1&&j<=t2)
{
if(b1[i][0]<b2[j][0])
//row numbers are not equal
{
b3[k][0]=b1[i][0];
b3[k][1]=b1[i][1];
b3[k][2]=b1[i][2];
k++;
i++;
}
else if(b2[j][0]<b1[i][0])
//row numbers are not equal
{
b3[k][0]=b2[j][0];
b3[k][1]=b2[j][1];
b3[k][2]=b2[j][2];
k++;
j++;
}
else if(b1[i][1]<b2[j][1])
//row numbers are equal, compare column
{
b3[k][0]=b1[i][0];
b3[k][1]=b1[i][1];
b3[k][2]=b1[i][2];
k++;
i++;
}
else if(b2[j][1]<b1[i][1])
//row numbers are equal, compare column
{
b3[k][0]=b2[j][0];
b3[k][1]=b2[j][1];
b3[k][2]=b2[j][2];
k++;
j++;
}
else
{
b3[k][0]=b1[i][0];
//row and column numbers are equal
b3[k][1]=b1[i][1];
b3[k][2]=b1[i][2]+b2[j][2];
k++;
i++;
j++;
}
}
while(i<=t1)
//copy remaining terms from b1
{
b3[k][0]=b1[i][0];
b3[k][1]=b1[i][1];
b3[k][2]=b1[i][2];
i++;
k++;
}
while(j<=t2)
//copy remaining terms from b2
{
b3[k][0]=b2[j][0];
b3[k][1]=b1[j][1];
b3[k][2]=b1[j][2];
j++;
k++;
}
b3[0][2]=k-1;
//set number of terms in b3
}
void printsparse(int b[MAX][3])
{
int i,t;
t=b[0][2];
printf("\n rowtcolumntvalue");
for(i=1;i<=t;i++)
{
printf("\n%d\t%d\t%d\t",b[i][0],b[i][1],b[i][2]);

}
what is the algorithm of a sparce matrix addition ​

Answer 1

this is complicated.

Explanation:

do not know