Question

#include <stdio.h>
int m = 0;
int find(int i) {
if(j>1){
j=find(j/10)-(j%10);
m+=j;
}else
j=0;
}
return j;
}
int main()
{
int i=8090:
int k:
k=find(i):
printf("%d", m);​

Answer 1

The solution is -82

Explanation:

• We are given

                $int m=0;\\int find(int j)\\{ if(j>1) { if(j>1) { j=find(j/10)-(j%10);\\ m+=j;\\ } else { j=0; } return m; }}int main(){ int i=8090; int k; k=find(i); printf("\%d",m);}$

• if(j>1 {if(j>1 j=find(j/10)-(j%10);m+=j;}else j=0;}return m}

int main()

{

 int i=8090;

 int k;

 k=find(i);

 printf("%d",m);

}

• Using the function "j=find(j/10)-(j%10), m+=j" for the input of '8090' we get the answer as -82