#include<stdio.h>
int main()
{
const char *5 = ";
char str[] = "1234";
S = str;
while(*s)
printf("%c", *s++);
return 0;
}
Answers
Answered by
4
Answer:
O don't know the answer bro
Answered by
0
"1234" is the required output
Explanation:
There are two errors in the given program.
1. In function ‘main’:
error:
‘S’ undeclared (first use in this function)
S = str;
2. In function ‘main’:
error:
expected identifier or ‘(’ before numeric constant
const char *5 = "";
After correcting the program:
#include<stdio.h>
int main(){
const char *t = "";
char str[] = "1234";
char *S = str;
while(*S){
printf("%c", *S++);
}
return 0;
}
hence, we get the output as: 1234
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