Question

#include <stdio.h>
main()
{int a!5) = { 5.1. 15, 20, 25}:
int1, ) k =1, ITI
i = ++aſil:
1 = alll++
m = ali++)
i= a ++i!
print dodd". ij. m),​

Answer 1

Answer:

compilation error

Explanation:

syntax error

Answer 2

Answer:

j=2

Explanation:

Yes j=2 because, we made increment in a[1] in

first statement which is 1, so it becomes 2.

Step-by-step explanation:

a[1]=1 and ++a[1] = ++1 = 2 , so i=2 and a[1] =2;

j=a[1]++ =2++ here j=2 because of Post-increment

m=a[i++] = a[ i ] because of

Post-increment so

m=a[2] = 15 and later increment in " i " to 3 ! So

values of i=3 , j=2 , m=15

Hope it helps you