#include <stdio.h>
void abc(char *s) {
if(s[0]='\0') {
return;
}
abc(s+1);
abc(s+1);
printf("%c",s[0]);
}
int main() {
abc("mysql");
return 0;
Answers
Answered by
1
Answer:
I may show error } missing
Answered by
0
Step-by-step explanation:
of 00#include <stdio.h>
void abc(char *s) {
if(s[0] == '\0') {
return;
}
abc(s+1);
abc(s+1);
printf("%c",s[0]);
}
int main() {
abc("mysql");
return 0;
}#include <stdio.h>
void abc(char *s) {
if(s[0] == '\0') {
return;
}
abc(s+1);
abc(s+1);
printf("%c",s[0]);
}
int main() {
abc("mysql");
return 0;
}
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