Question

#include <stdio.h>

void main()

{

    extern int i;

    i = 20;

    printf("%d", sizeof(i));

}

What would be the output of the above code?

​

Answer 1

Output : 20

extern int i; tell the compiler that int i is declared in some other file, in this code we have not included any other header file so it will cause compilation error.

Answer 2

Answer:

Explanation: extern int a; indicates that the variable a is defined elsewhere, usually in a separate source code module. printf("%d\n", a); it prints the value of local variable int a = 20. Because, whenever there is a conflict between local variable and global variable, local variable gets the highest priority