Computer Science, asked by shaibarasheedmi, 7 months ago

#include void main() { int x = 5; if (x < 1) printf("hello"); if (x == 5) printf("hi"); else printf("no"); }

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Answered by kaurmanveer

Answer:

Explanation:

the value of x is equal to 5, so it print hi

Answered by kaushanimisra97

Answer: This is a C program, when the program will run, It will define as an integer variable "x" and set its value to 5. It will then check if x is less than 1 and if x is equal to 5. Since x is not less than 1, the first if statement will be skipped. Since x is equal to 5, the second if statement will be executed and the output of the program will be "hi"

Explanation: Further, The third line is an 'else' statement, which is executed if the previous if statement is false. However, in this code snippet, the previous if statement is true, so the else statement will be ignored and will not be executed.

The program then calls the 'printf' function, which writes the string 'hi' to the standard output.

Finally, the 'main' function returns without any value, which is the default behavior for the C program's main function.

Learn more about C program here- https://brainly.in/question/36036687

Learn more about how C language features works here - https://brainly.in/question/192642

Project code = #SPJ2

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#include void main() { int x = 5; if (x < 1) printf("hello"); if (x == 5) printf("hi"); else printf("no"); }​

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#include void main() { int x = 5; if (x < 1) printf("hello"); if (x == 5) printf("hi"); else printf("no"); }