Including Jose, there are eight people in his family.
If order matters, how many ways can he arrange his family members into a row of five seats if Jose must sit in the first seat?
35
840
1,680
2,620
Answers
Answered by
1
Answer:
0
Step-by-step explanation:
because the no of members in his family is 8 and the no of seats is 5
Answered by
0
Given: 8 members
I.e. 1(Jose) + 7(remaining) = 8
Now,
Jose’s seat is fixed which can be arranged in 1p1 i.e. 1 way
And
Remaining 7 can be arranged in 7p4 I.e. 35 ways
Hence Total ways = 35 x 1 = 35
Hope this helped you.
I.e. 1(Jose) + 7(remaining) = 8
Now,
Jose’s seat is fixed which can be arranged in 1p1 i.e. 1 way
And
Remaining 7 can be arranged in 7p4 I.e. 35 ways
Hence Total ways = 35 x 1 = 35
Hope this helped you.
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