Question

Income of a businessman in last 5years is in the ratio of 3:2:6:5:7if the average income of last 5years in 4600 calculate income of each year

Answer 1

Answer -

• The businessman's income of all the five years are Rs 3000, Rs 2000, Rs 6000, Rs 5000 and Rs 7000 respectively.

To calculate -

• The businessman's income of each year.

Step-by-step explanation -

• Here, it is given that the income of a businessman in the last 5 years is in the ratio 3 : 2 : 6 : 5 : 7.

So let -

• The income of the businessman in the last five years be Rs "3x", "2x", "6x", "5x" and "7x" respectively.

Given that -

• The average income of the last five years is 4600.

We know that -

$\bigstar \: \underline{\boxed{\sf Average = \dfrac{Sum \: of \: all \: values}{Number \: of \: values}}}$

Here -

• Number of years = 5.

Therefore -

$\hookrightarrow \tt \dfrac{3x + 2x + 6x + 5x + 7x}{5} = 4600$

$\hookrightarrow\tt \dfrac{23x}{5} = 4600$

$\hookrightarrow \tt23x = 4600 \times 5$

$\hookrightarrow\tt23x = 23000$

$\hookrightarrow\tt x = \cancel{\dfrac{23000}{23} }$

$\hookrightarrow\tt x = Rs \: 1000$

________________________________

Hence, the businessman's income of each year is as follows -

$\bf 3x = 3 \times 1000 = Rs \: 3000.$

$\bf 2x = 2 \times 1000 = Rs \: 2000.$

$\bf 6x = 6 \times 1000 = Rs \: 6000.$

$\bf 5x = 5 \times 1000 = Rs \: 5000.$

$\bf 7x = 7 \times 1000 = Rs \: 7000.$

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Answer 2

Question :-

Income of a businessman in last 5years is in the ratio of 3:2:6:5:7if the average income of last 5years in 4600 calculate income of each year.

Solution :-

Here we given that the ratio of a income of a businessman in last 5 years and also we given that the average of last 5 years is 4600. And we need to find the income of each year.

Given :-

• Ratio of 5 years = 3 : 2 : 6 : 5 : 7
• Average income of 5 years = 4600

Need to find :-

• Income of each year

Here, we the income of each year be x and find the value of x by using average formula. Then we find each year income of that businesman.

Average Formula :-

${\bigstar \: {\red{\boxed{\rm{Average = \frac{Sum \: of\: all \: observations}{Total \: number \: of \: observations }}}}}}$

On using average formula we get,

$\sf:\longmapsto{}4600 = \frac{3x + 2x + 6x + 5x + 7x}{5} \\ \\ \sf:\longmapsto{}4600 = \frac{23x}{5} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{}23x = 4600 \times 5 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{}23x = 23000 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{}x = \frac{23000}{23} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{} \boxed{ \sf{x = 1000}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

• x = 1000₹

On Substituting x we get the values of each year income.

• 3x = 3(1000) = 3000
• 2x = 2(1000) = 2000
• 6x = 6(1000) = 6000
• 5x = 5(1000) = 5000
• 7x = 7(1000) = 7000

Income of each year :

• 1st year = 3000₹
• 2nd year = 2000₹
• 3rd year = 6000₹
• 4th year = 5000₹
• 5th year = 7000₹

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Learn more from brainly :

Q) Ratio of income of Mukesh and Suresh is 7:5 and ratio of their expenditure is 5:3. If

they save Rs. 1200 each , find the income of Mukesh?

(1) 2400

(2) 3000

(3) 3500

(4) 4200

(5) 4600

https://brainly.in/question/14074594