Question

Income of A is 10% more than income of B. Let B's income be x% less than A's income. find x

Answer 1

Answer:

9.09%

Step-by-step explanation:

income of B = b

Income of A = b + (10/100)b =  1.1b

b income less than A = 1.1b - b = 0.1b

x % = (0.1b/1.1b)*100 = 100/11 = 9.09%

Answer 2

B's income be 9.09% less than A's income.

Step-by-step explanation:

Let the income of B be y

Income of A is 10% more than income of B.

A's income = $y+10\%y=y+0.1y=1.1y$

Difference in incomes = 1.1 y-y=0.1y

B's income be x% less than A's income=$\frac{0.1y}{1.1y} \times 100 =9.09 \%$

Hence B's income be 9.09% less than A's income.

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