Increase The Volume Of 80 Cm Cube Of Gas By 20 Percent Ad Temperature Is 25 C At Constat P
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Hii Dear,
I suppose you're asking the final temperature.
◆ Answer -
T2 = 84.6 ℃
● Explanation -
# Given -
V1 = 80 cm^3
∆V/V1 = 20 %
T1 = 25 ℃ = 298 K
# Solution -
Final volume is calculated as -
V2 = V1 × (100+20)/100
V2 = 1.2 V1
According to Charles law -
V1 / V2 = T1 / T2
V1 / 1.2V1 = 298 / T2
T2 = 298 × 1.2
T2 = 357.8 K
T2 = 84.6 ℃
Therefore, final temperature of the gas will be 84.6 ℃.
Thanks dear...
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