Question

Increasing order of bond length of n o n o positive and o negative is

Answer 1

Answer:

NO+ has 10 valence electrons:

(Sigma2s)^2(Sigma*2s)^2(Pi2px,Pi2py)^4(Sigma2pz)^2

NO has 11 valence electrons:

Same as NO+ but add (Pi*2px,Pi*2py)^1

NO- has 12 valence electrons:

Same as NO but change ^1 at the end to ^2.

Your MO diagram for NO should look like this:

O is more electronegative than N so its orbitals are slightly lower in energy and the bonding orbitals are slightly more concentrated on O.

Note the odd electron is in a Pi*2p orbital.

Now draw two more MO diagrams for NO+ and NO-