Question

ind the equation of a line whose inclination with the x-axis is 150° and
hich passes through the point(3,-5).​

Answer 1

$slope \: of \: line \: = \tan( \alpha )$

slope = m = tan ( 150 ) = - 1/√3

$slope \: pointform \: for \: eqn \: of \: line \: \: is \\ y = mx + c$

for finding c sub y as -5 and x as 3

this gives c = √3 - 5

now eqn of line is

y = -x/√3 +√3-5

this gives √3y = -x + √3 - 5

this gives eqn of line is x + √3y +5 - √3