Question

ind the length of a rectangle given that its perimeter is 880 m and breadth is 88 m. ​

Answer 1

Correct Question :

Find the length of a rectangle given that its perimeter is 880 m and breadth is 88 m. 

Given :

• Breadth = 88 m
• Perimeter = 880 m

To find :

• Length ?

Solution :

➳ let the length be 'L'

� We know that,

➳ Perimeter of rectangle = 2(Length + Breadth)

• Now substitute the values :-

$\implies \: { \sf{880 = 2( L+ 88)}}$

$\implies { \sf{880 = 2L + 176}}$

$\implies{ \sf{880 - 176 = 2L}}$

$\implies { \sf{704 = 2L}}$

$\implies{ \sf{ \cancel \frac{704}{2} = 352}}$

$\implies { \green{ \boxed{ \sf{352 = L}}}}$

■ Hence, the length is 352 m.

_____________________________

$\star{ \underline{ \orange{ \sf{Check :}}}} \star$

$\implies { \sf{perimeter = 2(length + breadth)}}$

$\implies \: { \sf{880 = 2(352 + 88)}}$

$\implies { \sf{880 = 2 \times 440}}$

$\implies{ \sf{880 = 880}}$

${ \boxed{ \red{ \mathtt{checked}}}}✔$