ind the smallest number which when divided by 12 16 and 20 and leaves no remainder
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smallest number can be 2
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First we have to find the L.C.M. of 12,16 and 20
L.C.M. by Prime Facctorization method
12=2×2×3
16 = 2×2×2×2
20= 2×2×5
L.C.M.=2×2×2×2×3×5=240
Hence the required number is 240
L.C.M. by Prime Facctorization method
12=2×2×3
16 = 2×2×2×2
20= 2×2×5
L.C.M.=2×2×2×2×3×5=240
Hence the required number is 240
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