Question

ind the smallest number which when divided by 12 16 and 20 and leaves no remainder

Answer 1

smallest number can be 2

Answer 2

First we have to find the L.C.M. of 12,16 and 20
L.C.M. by Prime Facctorization method
12=2×2×3
16 = 2×2×2×2
20= 2×2×5
L.C.M.=2×2×2×2×3×5=240
Hence the required number is 240