Question

ind the value: (a^2-b^2)/(a-b)^2 = 4,if a=4 then find b?

1) 2/3
2) 4/3
3) 9/16
4) 1

Answer 1

put the value in that equation
(4^2-b^2)/(4-b)^2=4
(16-b^2)/16-8b+b^2=4
16-b^2=64-32b+4b^2
5b^2=48-32b
so this is quadratic so I am going to solve this OK by formula method I'll do it.
5b^2+32b-48=0
$formula = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a}$
= -32+-√1024-960/10
= -32+-√64/10
= -32+-8/10
b = -32+8/10 or b = -32-8/10
b = 24/10 or. b = -40/10
b = 2.4 or. b = -4

Answer 2

$\blue{\mathfrak{Here is your answer....... Hope this helps you....}}$