Question

ind the value of the expression x3−y3+x2+y2+3 by substituting x=−2 and y=1 .PLZ HELP ME

Answer 1

Answer:

Given,x=-2 and y=1

x3−y3+x2+y2+3

=-2^3-1^3+-2^2+1^2+3

=-8-1+4+1+3

=-9+8

=-1

Hope it helps you.