Question

ind the value of
the polynomtal y^2 + 6, when y= - 1​

Answer 1

Answer:

follow this step

Let f(y)=y

3

−5y−2y

2

+3

When y=−2

f(−2)=(−2)

3

−5(−2)−2(−2)

2

+3

=−8+10−8+3

=−16+13

=−3