Math, asked by litty8997, 1 year ago

Independence in the shape of a cylinder surmounted by a cone the diameter of cylindrical part is 2.1 M and 3 M respectively in the slant height of the conical part is 2.8 M find the cost of the Canvas mentor to make the 10th of the Canvas Juice available at the rate of rupees 500 per square metre

Answers

Answered by Anonymous
4

SOLUTION;

Given:

Height (h) of the cylindrical part = 2.1 m

Diameter of the cylindrical part = 3 m

Radius of the cylindrical part = 3/2 m

Slant height (l) of conical part = 2.8 m

Total canvas used = CSA of conical part + CSA of cylindrical part

= πrl + 2πrh

= πr(2h+l)

= (22/7)×3/2(2×2.1+2.8)

= (22/7)×3/2(4.2+2.8)

= (22/7)×3/2(7)

= 11×3

= 33 m²

Cost of 1 m² canvas = ₹ 500

Cost of 44 m² canvas = 33 × 500 = 16500

The cost of Canvas needed to make the tent= ₹ 16500

Hence,  it will cost ₹ 16500 for making such a tent.

HOPE THIS WILL HELP YOU...

Attachments:

litty8997: Thank you and sorry because there was a mistake when I am typing in the question
Answered by perfect2003
1

FIGURE IS IN THE ATTACHMENT]

SOLUTION;

Given:

Height (h) of the cylindrical part = 2.1 m

Diameter of the cylindrical part = 3 m

Radius of the cylindrical part = 3/2 m

Slant height (l) of conical part = 2.8 m

Total canvas used = CSA of conical part + CSA of cylindrical part

= πrl + 2πrh

= πr(2h+l)

= (22/7)×3/2(2×2.1+2.8)

= (22/7)×3/2(4.2+2.8)

= (22/7)×3/2(7)

= 11×3

= 33 m²

Cost of 1 m² canvas = ₹ 500

Cost of 44 m² canvas = 33 × 500 = 16500

The cost of Canvas needed to make the tent= ₹ 16500

Hence,  it will cost ₹ 16500 for making such a tent.

HOPE IT HELPS YOU

Attachments:
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