indeterminate form solve tanx-x÷x2tanx
Answers
Answered by
0
(tanx-x) / (x2tanx)
Separating the denominator, = tanx/ x2tanx - x/x2tanx
= 1/2x - 1/2tanx
= 1/2x - Cotx/2
Thus the inderminate form of (tanx-x) / (x2tanx) is 1/2x - Cotx/2
Separating the denominator, = tanx/ x2tanx - x/x2tanx
= 1/2x - 1/2tanx
= 1/2x - Cotx/2
Thus the inderminate form of (tanx-x) / (x2tanx) is 1/2x - Cotx/2
Similar questions