Math, asked by soumank9777, 1 year ago

India plays two matches each with west indies and australia. In any match the probabilities of india getting points 0, 1 and 2 are 0.45, 0.05 and 0.50 respectively. Assuming that the outcomes are independent, the probability of india getting at least 7 points is

Answers

Answered by Shaizakincsem
17

Thank you for asking this question. The options for this question are missing, here are the missing options:

A. 0.0625

B. 0.06875

C. 0.0825

D. 0.0875

E. 0.875

Answer:

India wins = W = 2 pt

India loses = L = 0 pt

India draws = D = 1 pt

Total matches played by India = 4

This means that the total points needs to be 7 at least

Either India wins all 4 matches

or (2) India wins 3 and draws 1

the probability of WWWW = (0.5)*(0.5)*(0.5)*(0.5) = 0.0625 (this is when if india wins 4 matches)

India wins 3 matches and draws 1: probability in that case = (0.5)*(0.5)*(0.5)*(0.05) = 0.00625

The 4 possible outcomes will be:

WWWD, WWDW, WDWW, DWWW

Total probability of India wins 3 matches and draws 1 = 4*(0.00625) = 0.025

probability of total points have to be at least 7 = 0.0625 + 0.025 = 0.0875

The correct answer is Option D

If there is any confusion please leave a comment below.



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