Indian Oil Drop experiment the following charges in arbitrary units were found on a series of oil droplets 2 point 30 into 10 raise to minus 56.9 into 10 raise to minus 15 1.38 into 10 raise to minus 14 5 point 75 into 10 raise to minus 15
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Now, we know how Millikan performed oil drop experiment.
→ The magnitude of the charge should be smallest and other charges should be integral multiples of that smallest charge.
So, in the data given here,
the smallest charge is 2 × 10-15
and all other charges are integral multiple of it.
Therefore,
The charge on electron = 2 × 10-15
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Answer:
1.15 * 10 ^15
Explanation:
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