Physics, asked by jogeswararaok8511, 1 year ago

indian young double slit experiment wave of wavelength lambda incident on to select in

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Answered by anki89
0
λ = y • d / (m • L)
, Young devised and performed an experiment to measure the wavelength of light. As discussed in the previous part of this lesson, it was important that the two sources of light that form the pattern be coherent. The difficulty confronting Young was that the usual light sources of the day (candles, lanterns, etc.) could not serve as coherent light sources. Young's method involved using sunlight that entered the room through a pinhole in a window shutter. A mirror was used to direct the pinhole beam horizontally across the room. To obtain two sources of light, Young used a small paper card to break the single pinhole beam into two beams, with part of the beam passing by the left side of the card and part of the beam passing by the right side of the card. Since these two beams emerged from the same source - the sun - they could be considered coming from two coherent sources. Light waves from these two sources (the left side and the right side of the card) would interfere. The interference pattern was then projected onto a screen where measurements could be made to determine the wavelength of light.

Answered by Anonymous
0

Answer:

The maximum intensity in young's double-slit experiment is I0. Distance between the slit is d=5λ, where λ is the wavelength of monochromatic light used in the experiment.

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