Chemistry, asked by teaquestion7070, 11 months ago

Indicate the number of unpaired electrons in. (i) p (ii)si (iii) cr (iv)fe (v)kr

Answers

Answered by rehabsadaf
3

hala mate,

(a) Phosphorus (P): 1s2 2s2 2p6 3s2 3p3

No of unpaired electron = 3

 

(b) Silicon (Si): 1s2 2s2 2p6 3s2 3p2

No of unpaired electron = 2 (since p orbital can have maximum 6 electron )

 

(c) Chromium (Cr): 1s2 2s2 2p6 3s2 3p6 4s1 3d5

No of unpaired electrons = 6 (since 1 electron is to be added to 4s & 5 electron to be added to 3d orbital.

 

(d) Iron (Fe): 1s2 2s2 2p6 3s2 3p6 4s2 3d6

No of unpaired electrons = 4

 

(e) Krypton (Kr): 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6

Since all orbitals are fully occupied, there are no unpaired electrons in krypton.

hope it helps!

Answered by Likanmendali
0

Answer:

1. 3

2. 2

3. 6

4. 4

5. There is no unpaired electrons

Similar questions