Indicate the oxidizing and reducing agents in the following reaction : 2Cu2+ + 4I-2CuI + I2
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Answered by
24
Answer:
Cu is reduced, so Cu{2+} is the oxidizing agent.
I is oxidized, so I{-} is the reducing agent.
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Answered by
0
Answer:
Cu2+ is oxidizing and I (-) is the reducing agent
Explanation:
As Cu is reduced And I is Oxidized .
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