INDIRECT PROPORTION- 3 masons can build a room in 20 days. How many days would it take 10 masons to build the same room?
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INDIRECT PROPORTION- 3 masons can build a room in 20 days. How many days would it take 10 masons to build the same rooms
your answer please mark as brinalys
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6 days
Step-by-step explanation:
for indirect proportion, product is constant
so, no. of masons * days required = 3 * 20 = 60
once again, no. of masons * days required = 10 * no. of days = 60
10 * x = 60
so, no. of days = 6 days
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