Question

Indium antimonide has a band gap of 0.23 eV between the valence and the conduction band. Find the temperature at which kT equals the band gap.

Answer 1

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Explanation:

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Answer 2

Indium antimonide has a band gap of 0.23 eV between the valence and the conduction band,at which the thermal energy kT equals the indium antimonide’s band gap.

Explanation:

• It is given that the band gap between the valance band and the conduction band, $E=0.23 \mathrm{eV}$
• Constant of Boltzmann, $k=1.38 \times 10^{-23} \mathrm{J} / \mathrm{K}$
• It is to be found that the temperature at which the thermal energy kT equals the indium antimonide’s band gap.

Therefore,

$k T=E$

$\Rightarrow 1.38 \times 10-23 \times \mathrm{T}=0.23 \times 1.6 \times 10-19$

$\Rightarrow \mathrm{T}=0.23 \times 10-191.38 \times 1.6 \times 10-23$

$\Rightarrow \mathrm{T}=0.2666 \times 104$ which is approximately 2670 K.