Inecuaciones fraccionarias
1. +7
−4
≥ 0
2. 1−2
+2
≤ −2
3. 2+1
≥ 1
4. 4−1
+6
≥ 2
5. 12−18
−9
≥ −6
6. +8
−1
≥ 2
7. 7−21
+14
≤ −35
8. 2−4
+6
≤ 1
9. 4−11
+4
≤ −2
10. 4−36
−27
≥ 7Inecuaciones fraccionarias
2do Año Bachillerato en Contabilidad paralelo
1. +7
−4
≥ 0
2. 1−2
+2
≤ −2
3. 2+1
≥ 1
4. 4−1
+6
≥ 2
5. 12−18
−9
≥ −6
6. +8
−1
≥ 2
7. 7−21
+14
≤ −35
8. 2−4
+6
≤ 1
9. 4−11
+4
≤ −2
10. 4−36
−27
≥ 7
Answers
Answered by
0
Answer:
Medium
Solution
verified
Verified by Toppr
We know that in a circle of radius r unit, if an arc of length l unit
subtends an angle θ radian at the centre, then θ=
r
l
Therefore, for r=100 cm, l=22 cm, we have
θ=
100
22
radian=
π
180
×
100
22
degree=
22×100
180×7×22
degree
=
10
126
degree=12
5
3
degree=12
∘
36
′
,[∵1
∘
=60
′
]
Answered by
1
Answer:
the equation 2 x 3 = 6, the numbers two and three are factors.
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