Question

Inertia torque of a metal rod in a suspension manner for the pepper

Answer 1

dt

2

d

2

θ

+(mgL/2I)θ=0

The restoring torque is −(mgL/2)sinθ. For smaller angles, sinθ=θ AND torque is given by I

dt

2

d

θ

. Equating both, we get,

dt

2

d

2

θ

+(mgL/2I)θ=0