Science, asked by shivamraj2512, 11 days ago

inF2 population of1600plalntsl number of plalnts with Yyrr genotype are​

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Answered by ansulsharma
0

cross is made between homozygous yellow round seeds(YYRR) to another homozygous green wrinkled seeds(yyrr). In the F1 generation, all plants are heterozygous yellow round(YyrRr). When this plant is subjected to self-pollination, in the F2 generation, 9 plants are Yellow round, 3 plants are yellow wrinkled, 3 plants are green round and 1 plant is green wrinkled are formed.

The dihybrid phenotypic ratio is 9:3:3:1. So, in the dihybrid cross, 800 individuals are formed, in this 450 are yellow round 150 are yellow wrinkled, 150 are green round, 50 are green wrinkled.

The dihybrid phenotypic ratio is 9:3:3:1. So, in the dihybrid cross, 800 individuals are formed, in this 450 are yellow round 150 are yellow wrinkled, 150 are green round, 50 are green wrinkled.So, the correct option is ‘150’.

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