Math, asked by Vishikaagrawal, 2 months ago

InFig.D is the midpoint of side BC and AE⊥BC.IfBC=aAC=b, AB=c,ED=x,AD= p and AE = h, prove that: (b2 – c2) = 2ax

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Answered by ifxhn
1

Answer:

(i) In right-angled triangle AEC, applying Pythagoras theorem, we have:

(ii) In right-angled triangle AEB, applying Pythagoras, we have:

(iii) Adding (i) and (ii), we get:

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