Ingrid kicks a football with an initial velocity of 12 m/s at an angle of 45° relative to the ground. The horizontal component of the initial velocity to the nearest tenth is m/s.
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Ingrid kicks a football with an initial velocity of 12 m/s at an angle of 45° ... The horizontal component of the initial velocity to the nearest tenth is [Blank] m/ s. 8.5.
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Given,
v = 12m/s
the angle of flight, θ= 45°
To find,
, the horizontal component of 'v' to the nearest tenth.
Solution,
When the ball is kicked its velocity has a verticle as well as a horizontal component.
The verticle component is given by = θ
and the horizontal component, θ
Here, we have to find the verticle component.
putting the values,
θ = 12cosθ
= 12cos45°
= 12×1/
= 8.485
= 8.5 (rounded to the nearest tenth)
∴ the horizontal component of the initial velocity of the ball,
= 8.5 m/s
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