Inis triangle ABCthe midpoint of BC. E is the foot of the perpendicular from A to BC (lie on BC), and F is the foot of the perpendicular from D to AC. Given that BE=5 EC=9
and the area of triangle ABC is 84. Then the value of EF i
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Let DE and DF be the perpendiculars from D on AB and AC respectively.
In △s BDE and CDF, DE=DF (Given)
∠BED=∠CFD=90
∘
BD=DC (∵ D is the mid-point of BC)
∴ △BDE≅△CDF (RHS)
⇒ ∠B=∠C (cpct)
⇒ AC=AB (Sides opp. equal ∠s are equal)
⇒ △ABC is isosceles.
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