Chemistry, asked by soumyadongare256, 3 days ago

Initial concentration of A is twice the initial concentration of B. At equilibrium concentration of A and C are same then equilibrium constant for the reaction is

A(g) + B(g) ---> 2C(g)

DISCLAIMER: SCAMMING KILLS THE PHONE

Answers

Answered by priyankachavla281

Answer:

Initial concentration of A is twice the initial concentration of B. At equilibrium concentration of A and C are same then equilibrium constant for the reaction is

A(g) + B(g) ---> 2C(g)

DISCLAIMER: SCAMMING KILLS THE PHONE

Explanation:

Initial concentration of A is twice the initial concentration of B. At equilibrium concentration of A and C are same then equilibrium constant for the reaction is

A(g) + B(g) ---> 2C(g)

DISCLAIMER: SCAMMING KILLS THE PHONE

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