Initial distance between a girl and bus is 50m. bus starts moving with 1m/s² acceleration. girl starts moving simultaneously with velocity u. what should be minimum velocity of girl to catch bus
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Let the student travels distance s
t
in time t and catches the
bus.
S
1
=ut (1)
Distance travelled by the bus in time t
s
2
=0+
2
1
at
2
.(2)
The student is able to catch the bus if,
s
1
=d+s
2
ut=d+
2
1
×1×t
2
Or, 2ut=2d+t
2
Or, t
2
−2ut+2d=0
Solving the quadratic equation
t=
2
2±
4u
2
−8d
=1±
u
2
−2d
For t to be real
u≥
2d
u≥
2×50
=10m/s.
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