Question

Initial speed of you of a projectile projected from ground reduces by 50% on reaching the maximum height the angle of projection of projectile with the horizontal will be

Answer 1

$\color{red}\huge{\underline{\underline{GIVEN\dag}}}$

• Initial speed of projectile decreases by 50% at max height.

$\color{red}\huge{\underline{\underline{SOLUTION\dag}}}$

Let $'u'$ be the velocity at which it was projected.

Then,

At maximum height velocity will be

$u \cos( \theta)$

but its given that, velocity reduces by 50%

$\implies u \cos( \theta) = 50\% \: of \: u$

$\implies u \cos( \theta) = u \times \frac{50}{100}$

$\implies u \cos( \theta) = u \times \frac{1}{2}$

$\implies \cos( \theta) = \frac{1}{2}$

$\implies \cos( \theta) = \cos(60 \degree)$

$\orange{ \boxed{\therefore \theta = 60 \degree}}$

HOPE THAT HELPS!!

Answer 2

.

Let 'u' be the velocity at which it was projected.

Then,

At maximum height velocity will be

$\longrightarrow \: u \cos(0)$

But,then it's given that , velocity reduces by 50%

So,

$\longrightarrow u \cos(0) =50\% \: of \: u \\ \longrightarrow \: u \cos(0) = u \times \frac{50}{100} \\ \longrightarrow \: u \cos(0) = u \times \frac{1}{2} \\ \longrightarrow \: \cos(0) = \frac{1}{2} \\ \longrightarrow \: \cos(0) = \cos(60 \: degree)$

Hence,

cos(0)=60°

Hope it helps!

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