Question

Initial velocity 2 m/s along +ive x direction and it accelerates uniformly at the rate of 0.40 m/s^2 find distance travelled by it in 1st 3 seconds

Answer 1

u=2m/s
a=0.40m/s^2
t=3s
s=ut+1/2at^2
s=2(3)+1/2(0.4)×3^2=7.8m

Answer 2

GiveN :-

• A partial start with an initial velocity 2m/s along the positive x- direction and in accelerates uniformly at a rate of 0.60m/s² .

To FinD :-

• The distance traveled by it in the first 3 sec.

SolutioN :-

Here the initial Velocity of the particle was 2m/s and acceleration was 0.4 m/s² .We need to find the distance travelled in 3 seconds . Here we can use the second equation of motion.

★ Using the second equation of motion :-

$\sf:\dashrightarrow \pink{ s=ut + \dfrac{1}{2}at^2}\\\\\sf\dashrightarrow S_5 = (2m/s)(3s)+\dfrac{1}{2}(0.4 \ m/s^2)(3s)^2 \\\\\sf\dashrightarrow S_5 = \bigg(6+ \dfrac{2}{10}\times 9 \bigg) m \\\\\sf\dashrightarrow S_5 =( 6 + 1.8 ) m\\\\\sf\dashrightarrow \underset{\blue{\sf Required\ Answer}}{\underbrace{\boxed{\pink{\frak{ Distance _{(5\ seconds)}= 7.8 \ m }}}}}$