Question

Initial velocity of A car is 5 m/s. It is accelerating at an acceleration of 5m/s^2.
Its final velocity is 0 m/s. Then find the distance traveled.
By the third equation of motion. ​

Answer 1

Explanation:

third eqn of motion,

v²- u² = 2as

0² - 5² = 2× -5 × s

-25 = -10s

s = 2.5

so distance travelled = 2.5m