Question

initial velocity of a particle is 10 metre per second and it's retarding force is 2 metre per second square what is the distance travelled by the particle in fifth second of its motion
a. 1 m
b. 19 m
c. 50 m
d. 75 m​

Answer 1

Answer:

a. 1m

Explanation:

u=10m/s

acceleration=-2m/s^2

Sn=u+a/2(2n-1)

S5=10+(-2/2)(2×5-1)

S5= 10-9

S5=1m