Question

initial velocity of ballis 5 m/s under retardation stops in5 sec.find the value of retardation.​

Answer 1

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore Acceleration=-1\:ms^{2}}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a ball that is in motion with initial velocity 5 m/s and after 5 sec the ball stop motion.

• We have to find the retardation on ball to stop after 5 sec.

$\underline \bold{given: } \\ \implies Initial \: velocity(u) = 5 \: m/s \\ \\ \implies Time(t) = 5 \: sec \\ \\ \implies Final \: velocity(v) = 0 \: m/s \\ \\ \underline \bold{To \: Find: } \\ \implies Acceleration = ?$

• According to given question :

$\bold{Using \: First \: equation \: of \: motion : } \\ \implies v = u + at \\ \\ \bold{Putting \: values : } \\ \implies 0 = 5 + a \times 5 \\ \\ \implies - 5 = a \times t \\ \\ \implies a = \frac{ \cancel{ - 5}}{ \cancel5} \\ \\ \bold{\implies a = - 1 \: m /{s}^{2} } \\ \\ \bold{\therefore Retardation \: of \: 1 \: m/ {s}^{2} }$

Answer 2

Answer____

• Retardation = -1 m/s^2

Step-by-step explanation:

$\bold{using \: first \: equation \: of \: motion : } \\ \implies v = u + at \\ \\ \bold{putting \: values : } \\ \implies 0 = 5 + a \times 5 \\ \\ \implies - 5 = a \times t \\ \\ \implies a = \frac{ { - 5}}{ 5} \\ \\ \bold{\implies a = - 1 \: m {s}^{2} } \\ \\ \bold{\therefore retardation \: of \: 1 \: m {s}^{2} }$