Question

Initial velocity with which a body is projected is 10m/s and angle of projection is 60 degrees. Find the range R.

Answer 1

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Answer 2

The range of the projectile is 8.83 meters.

Explanation:

It is given that,

Velocity of projection, v = 10 m/s

Angle of projection, $\theta=60^{\circ}$

The range of a projectile is equal to the horizontal distance covered by the projectile. It is given by the formula as :

$R=\dfrac{v^2\ sin2\theta}{g}$

$R=\dfrac{(10)^2\ sin2(60)}{9.8}$

R = 8.83 meters

So, the range of the projectile is 8.83 meters. Hence, this is the required solution.

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