initial velocityis 0.5m/s velicity decreases the rate of 0.05m/s.square how much time will it take for the body to stop
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1
hi buddy
here's your answer looking for
here,
u=.5m/s
v=0m/s
a=-.05m/s^2
now, solution is given in attached image
hope you are satisfied with my answer
here's your answer looking for
here,
u=.5m/s
v=0m/s
a=-.05m/s^2
now, solution is given in attached image
hope you are satisfied with my answer
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Answered by
0
u=0.5m/s
v=0m/s
a=-0.05m/s^2
v^2=u^2-2as
(0)²=(0.5)²-2(0.05)s
0=0.25-0.10s
-0.25=-0.10s
s=-0.25/-0.10
s=5/2
s=2.5 m
plz mark as brainlist answer
v=0m/s
a=-0.05m/s^2
v^2=u^2-2as
(0)²=(0.5)²-2(0.05)s
0=0.25-0.10s
-0.25=-0.10s
s=-0.25/-0.10
s=5/2
s=2.5 m
plz mark as brainlist answer
AMAYTRIPATHI:
wrong configuration
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